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On Tue, Sep 30, 2014 at 11:21 AM, Roger Harman <roger.harman@xxxxxxxxxxx> wrote:
Thanks Vern.

The "pick K of N" is a pretty easy concept. For this application, however, K is a variable ranging 1..N. A bit different to apply.

But Vern did account for the variability of K. 1023 *is* the answer
to your question.

Let's break it down:

There are 10 ways to choose 1 from 10.
45 ways to choose 2 from 10.
120 ways to choose 3 from 10.
210 ways to choose 4 from 10.
252 ways to choose 5 from 10.
210 ways to choose 6 from 10.
120 ways to choose 7 from 10.
45 ways to choose 8 from 10.
10 ways to choose 9 from 10.
1 way to choose 10 from 10.

10 + 45 + 120 + 210 + 252 + 210 + 120 + 45 + 10 + 1 = 1023.

Which is exactly what Vern said.

John Y.

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