Re: definintion of signed integer?

I'm pretty sure you're being bit by eval's handling of intermediate results...

Since PositiveValue is an unsigned integer, and 21 is a constant that
could also be considered an unsigned integer, eval is treating the
results as an unsigned integer which obviously won't hold a negative
value.

Solution:
1) redefine PositiveValue as a signed integer
2) let eval know you're dealing with signed values
a) NegativeValue = %int(PositiveValue) - 21;
b) NegativeValue = PositiveValue + (-21);

note that 2a) would blow up given a PositiveValue greater than 127.

I'd go with option 1) myself....

HTH,
Charles



On Mon, Sep 27, 2010 at 4:04 PM, Koester, Michael
<mkoester@xxxxxxxxxxxxx> wrote:

I have a variable defined "3i 0", local to a subprocedure that I expect
could be any whole number value from -128 to +127, per my understanding
of a signed integer.  When my subprocedure puts what I expect to be a
minus 18 into the field, I get the dreaded "MCH1216 -  too small to hold
result" crash & burn.

I'm sure I can fix it instantly by defining packed numerics, but I need
to understand the rules.

D PositiveValue            3u  0
D NegativeValue            3i  0
 /free
 PositiveValue = 3;
 NegativeValue = PositiveValue - 21;
  [down in flames we go]
 /end-free

What could be so tough about subtracting 3 from 21 and expecting -18?
Please set me straight here.  It's an SQLRPGLE program on a 6.1 box.

Many thanks.
Michael Koester

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