Hey Dennis,
I have absolutely no experience using the regex stuff, but the syntax of the call in your code example includes "match(1)" as the 3rd parameter. This doesn't restrict the number of find instances (1) does it?
rc = regexec(regEx
: findWithin
: %Elem(match)
: match(1)
: *Zero
I couldn't quickly find any documentation that seemed to apply. Just stabbing into the darkness.
Steve Needles
Northland Insurance
(651) 310-4203
-----Original Message-----
From: rpg400-l-bounces@xxxxxxxxxxxx [mailto:rpg400-l-bounces@xxxxxxxxxxxx] On Behalf Of Dennis Lovelady
Sent: Wednesday, February 03, 2010 10:12 AM
To: 'RPG programming on the IBM i / System i'
Subject: Regular Expression multi-match not as expected
Folks, I'm getting unexpected result from Regular Expression matching on
System i at V5R3. You can see the code in question at
http://code.midrange.com/e15d4eb99d.html.
I expect the expression to match on both the word "one" and the second
position of the word "none" but the search seems to stop after the first
match. (I can see that it has initialized all elements of match, however,
for whatever that's worth.) To see the issue, run in debug mode and set a
breakpoint at the line that contains "Match(es)". At that point, rc should
be zero (and it is); the first element of match should point to the second
character of done. (all good so far). But the second element of match
should point to the word "one" and it doesn't.
Can you see what might be wrong with this? Thanks.
Dennis E. Lovelady
AIM: delovelady MSN: fastcounter@xxxxxxxxxxxx
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http://www.linkedin.com/in/dennislovelady>
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