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Would this work?
x = 1.01;
if (%rem(x : 1) <> 0);
x = (2 * x) + 1;
else;
x = (2 * x);
endif;

James R. Perkins


On Fri, Feb 27, 2009 at 14:38, Lance Gillespie <lgillespie@xxxxxxxx> wrote:

I have a situation where I need my results rounded up if they are not
exact.

As in:
2 * 1.01 = 3
2 * 1.50 = 3
2 * 1.51 = 4

The source and target numbers are 7,0 and the factor is a constant.

I thought:

target = %dech(source * 1.01) : 7 : 0)

or maybe

target = %dech(source * 1.01) : 9 : 2)

would do it, but no joy.

I suppose I could do the calcs twice with %dec, once to a 7,0 result and
once to a 9,2 result
(assuming %dec truncates) and then add one to the 7,0 result if the two are
not equal, but
I would rather not.

Is there some way to force these calcs to round up if not exact?

Thanks,
Lance




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