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In answer to your question - yes, provided the 11 in "reade (XX1: 11)
XXFILE;" is in fact the second key of the 3 and not the third key
(Hope that made sense)


Alan Shore
Programmer/Analyst, Direct Response
E:AShore@xxxxxxxxxxx
P:(631) 244-2000 ext. 5019
C:(631) 880-8640
"If you're going through Hell, keep going" - Winston Churchill

rpg400-l-bounces@xxxxxxxxxxxx wrote on 08/14/2008 04:44:43 PM:

nah. Tried it. It didn't work. Acted exactly the same.

I am thinking that it may have to do with the "reade (XX1: 11) XXFILE;"
line? Does this reade with two keys act the same as a 2-field klist in
factor 1 when run against a 3-key file?



Michael_Schutte@xxxxxxxxxxxx wrote:
just for sh*ts and giggles try adding the name of the file to the EOF
bif.

Dow not %EoF(XXFILE);


I've seen it before and that's why I always use the name of the file in
the
bif.


Michael Schutte
Admin Professional
Bob Evans Farms, Inc.

rpg400-l-bounces@xxxxxxxxxxxx wrote on 08/14/2008 03:26:31 PM:


READE in Free form, and dow not %eof

Something is not working the way I expected.

I have a file with three keys. I want to read all records (53 of
them)
where key1 = the value in XX1 and key2 = 11.

Here's what I think I have done:
FXXFILE if e k disk
XX1 = 'O';
// Retrieve XXFILE record:
setll (XX1: 11) XXFILE;
reade (XX1: 11) XXFILE;
dow not %eof;
... stuff
reade (XX1: 11) XXFILE;
enddo;

This all works as I expect in debug *except* that once the 53 records
are retrieved nothing more that I can see happens. It acts like an
endless loop, but I just don't know what is happening.

Any suggestions would be most welcome.



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Booth Martin
http://www.Martinvt.com
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http://www.Martinvt.com
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