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I don't have access to a system right now, but will this work?

d today s d

today = %date();
%subdt(today: *days) = 1;




On Sat, Jul 5, 2008 at 8:03 PM, Simon Coulter <shc@xxxxxxxxxxxxxxxxx> wrote:


On 06/07/2008, at 10:40 AM, John Ross wrote:

%Date()-%days(UDAY-1)

Note: UDAY is the Job date, so if the job runs multiple days, it
may not
work for you.

Never mind MAY ...

Given that %date returns system date and UDAY is job day it WILL not
work--at least not reliably. SBMJOB DATE(??????), CHGJOB DATE
(??????), or simply running past midnight will all break this algorithm.

Regards,
Simon Coulter.
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