Re: %subst as a result.

FYI, I'm not sure where but I remember something about %len() being a
better fit than %size() for this getting the length of a field.  %size
is number of bytes occupied, not necessarily the actual length of the
field.

I think it's possibly just for numerics though - for instance, a
packed field would have a %size of 4, but a %len of 7.  similar
shenanigans with integers, binary, etc.

at any rate, I've always used %len when looking at the length of any
field, alpha or numeric, and have never been disappointed.

On 3/20/06, rick baird <rick.baird@xxxxxxxxx> wrote:
> your divide by two could result in an intermediate answer with decimal
> positions.
>
> decimal positions are invalid for the param of %subst()
>
> try this
>
> d $beg      s                  3s 0
>
> C eval   $beg = (%size(Title) - (%size(%trim((cTitle)) / 2)
>
> C   eval  %subst(Title:$beg) = %trim(ctitle)
>
>
>
>
>
> On 3/20/06, Booth Martin <booth@xxxxxxxxxxxx> wrote:
> > %subst as a result.
> >
> > I can't figure out two problems I believe are simply solved by others.
> >
> > I wish to populate a field with a constant, and center the text.
> >
> > Lets say we have a field called Title that is 40/alpha.
> > Lets say we have a constant field of cTitle, with a value of 'Screen Title"
> >
> > I know how to do this with several lines of code, but I'd like to use %subst
> >
> > I believe this should work, but it doesn't compile:
> >
> >   C   eval  %subst(Title:
> >   C            ((%size(Title) - %size(cTitle) / 2)
> >   C             = cTitle
> >
> > This does not compile and I can't see why not.
> >
> > If it did compile I would then ask my other question. How does one also
> > clear the target field?  Must that be done first?
> >
> > --
> > -----------------------------------
> > Booth Martin
> > http://martinvt.com
> > -----------------------------------
> > --
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