Re: Date Field block size

On 24/12/2005, at 4:49 AM, Tony Carolla wrote:

DSPFD indicates that the record length is 18. Now, I know once I READ, the field that will be created to represent FMUPDAT is a length 10 (ISO) field.

But on disk, it is a four-byte field.  So my question is this:  My

understanding is that a size of I/O from disk is 128K. If this is to be read directly from disk, into the buffer when the READ op executes, will

there be a need for ten bytes to store this field?

Yes.

I know that the single variable inside the program will never see that four-byte value directly, but why would a disk buffer need to know anything else other than

the four bytes?

Regards,
Simon Coulter.
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