Re: Another SQL issue

V5R2 does not support qualified data structures in SQL.

I am given to believe that SQL has a lot of these little limitations that 
are subject to change in the not too distant future.  However, if you 
can't find the problem here:
http://www-912.ibm.com/n_dir/nas4apar.nsf/nas4aparhome
Then I would still open up a ticket on it.  I couldn't find this 
particular problem, but perhaps I was searching wrong.

If you don't like the answer on the ticket then I would submit a Design 
Change Request.
http://faq.midrange.com/index.pl?_highlightWords=dcr&file=189

Rob Berendt
-- 
"They that can give up essential liberty to obtain a little temporary 
safety deserve neither liberty nor safety." 
Benjamin Franklin 





"Wills, Mike N. (TC)" <MNWills@xxxxxxxxxxxxxx>
Sent by: rpg400-l-bounces+rob=dekko.com@xxxxxxxxxxxx
08/12/2003 03:04 PM
Please respond to RPG programming on the AS400 / iSeries
 
        To:     "'RPG programming on the AS400 / iSeries'" 
<rpg400-l@xxxxxxxxxxxx>
        cc: 
        Fax to: 
        Subject:        Another SQL issue


Well, I don't know if I am doing something wrong or not, but now I get
compiler errors because SQL isn't using the qualified data structure field
names I have in my program. Is this a issue or am I doing it wrong?

I have:
       // SQL Fields
     D InvCountDS      DS            44    Qualified
     D  CompanyName                  30 
     D  CompanyNum                    4  0
     D  POInvFlag                     1
     D  Count                         9  0

     D POCountDS       DS            43    Qualified
     D  CompanyName                  30
     D  CompanyNum                    4  0
     D  Count                         9  0

SQL puts in:

C*Exec SQL 
C* FETCH POCOUNT INTO :PoCountDS 
C*End-Exec 
C                   Z-ADD     -4            SQLER6 
C                   CALL      'QSQROUTE' 
C                   PARM                    SQLCA 
C                   PARM                    SQL_00035 
C     SQL_00038     IFEQ      '1' 
C                   EVAL      COMPANYNAME = SQL_00040 
C                   EVAL      COMPANYNUM = SQL_00041 
C                   EVAL      COUNT = SQL_00042 
C                   END 
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