RE: Converting alpha dates to date data type fields (m/d/yy)

Duane, Gary, Booth

All of these would work if i were only worried about the month.  I also
have to worry about the day.

I could get:

1/1/02
1/10/02
10/1/02
10/10/02

all of which need to be converted to an *iso date.

which means i'm probably going to have to scan for slashes and substring it
out.

thanks anyway


>>Duane said:

Try this. Translate " " to "0" and then convert.
Duane

>>Gary said:

d $CDate          S               D   DATFMT(*ISO)

c                   if        %len(%trim(CBDATE)) = 7
c                   eval      CBDATE = '0' + %trim(CBDATE)
v                   endif
c     *mdy/         move      CBDATE        $CDate

>>Booth said:

Maybe define an 8-char field, then:

   C      MOVE   '00000000'  Tmp8
   C      MOVE   CBDATE    Tmp8

Use Tmp8 for your existing calcs.   Not neat and spiffy, but reliable and
clear.


I originally wrote:
>
> I'm trying to convert a date field from an ascii file to an rpg date data
> type.
>
> The date coming in is an 8 byte alpha field in the format of mm/dd/yy BUT
> when the month or the day is less than 10, it only serves one digit -
>
> i.e. 09/05/02 shows up as 9/5/02.  I have no control over what this file
> looks like when it arrives.
>
> I tried converting it using the following code:
>
> d $CDate          S               D   DATFMT(*ISO)
>
> c     *mdy/         move      CBDATE        $CDate
>
> but I get an error that '8/23/02 ' is an invalid date.
>
> short of searching for slashes and manipulating this alpha field with
> substrings to extract the date, is there an easy way to convert these?
>
> thanks,
>
> Rick