RE: Help... %Len initializing field ?

Hi Buck,

Problem is that I don't know the length in advance.

I pass the pointer to a C function to store it's result, and get in the
return value the actual length it stored in there.  Only then I can change
the length.

Anyway, solved it with a 5U 0 field overlayed on the varying field... but I
had the impression that this worked before.

Kind regards,
Paul

-----Original Message-----
From: Buck Calabro [mailto:Buck.Calabro@commsoft.net]
Sent: 03 June, 2002 15:48
To: rpg400-l@midrange.com
Subject: RE: Help... %Len initializing field ?


>Has this always been like that ?
>
>DBuffer           S          32767    Varying
>DpFixed           S               *
>DFixed            S          32767    Based(pFixed)
>
> /free
>  pFixed = %Addr(Buffer) + 2;
>  Fixed = 'Hello';
>  %Len(Buffer) = %Len(Buffer) + 5;
>  *INLR = *On;
>  Return;
> /end-free
>
>Given this sample... I end up with Buffer containing 5
>blanks... and not my 'Hello' ?

Paul, I think this has always been this way.  When the program starts,
Buffer contains 'undefined' data.  When I set the length explicitly, the
compiler initialises the string to blanks up to the new length (5 blanks.)
This will work as you expect if you set the length prior to setting 'Fixed'.
  --buck

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