Re: more based() %addr array questions!!! found my problem:

Hi Richard,

One of the often ignored facts about pointers - you don't need to define them,
the compiler will define them for you.
Since you had a field based on $QxChkBase, but hadn't defined $QxChkBase the
compiler went ahead and defined it for you. It's RPG - but not as we know it
:-).

HTH

Paul Tuohy

Richard B Baird wrote:

> never mind on why my pointer was not set....  but now I even more confused.
>
> my pointer was not set because I misspelled my pointer variable name -
> $QxChkBase should have been $QzChkBase.
>
> which begs the question - how did my program compile?  $QxChkBase is not a
> valid variable or pointer.
>
> Hans? Barbara?  Stop me before I kill again!
>
> Rick
>
> ---my original message---
>
> Now I'm really confused.
>
> I'm just now getting around to testing what I thought was a sound solution
> to my redefining data structure fields as an array.  here is the code:
>
> DDSINPUT        E DS                  EXTNAME(DSUPDPAG)inz
>
>  * dsupdpag has QZAMT1-12 and QZCHK1-12 defined.
>
> D $QzAmtBase      S               *   inz(%addr(QZAMT1))
> D $QzAmt          S                   like(QZAMT1) based($QzAmtBase)
> D                                      dim(12)
> D $QzChkBase      S               *   inz(%addr(QZCHK1))
> D $QzChk          S                   like(QZCHK1 ) based($QxChkBase)
> D                                      dim(12)
>
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