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OK, let's hit these a little at a time...

>D SS              S              1    DIM(11)
Array of characters, 11 elements, each one character long

>D                 DS
>D  SSNO                   1     11
>D  S1                     1      3
>D  S3                     4      7
>D  S5                     8     11
Data structure which shares storage between SSNO, S1, S2 and S3.
SSNO ABCDEFGHIJK
S1   ABC
S2   DEFG
S3   HIJK

>c    MOVEA     S1            SS(1)
SS ABCxxxxxxxx
Because S1 is three bytes long, it loads the first three elements of array
SS

>c    MOVEA     S3            SS(5)
SS ABCxDEFGxxx
Because we told it to start at element 5, we'll skip element 4, which will
remain whatever it was before this operation. Because S3 is four bytes long,
it gets loaded into elements 5,6,7 and 8, leaving all the other elements
"as-is."

>c    MOVEA     S5            SS(9)
SS ABCxDEFGHIJ
Note that the "K" wasn't loaded in the array because it is 4 characters
long, starting at element 9, so 9,10,11 get loaded.

>C                   MOVEA     '-'           SS(4)
SS ABC-DEFGHIJ

>C                   MOVEA     '-'           SS(7)
SS ABC-DE-GHIJ

I hope this helps clarify what the code is doing.
  --buck


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