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  • Subject: RE: page n of x
  • From: "Jay Myrick" <jmyrick@xxxxxxxxxxx>
  • Date: Mon, 11 Sep 2000 18:34:28 -0500
  • Importance: Normal

Buck,

My suggestion was for a simple report, but it can be applied with the SQL
statement joining multiple files same priniciples would apply. I have
serveral programs that join 5 to 8 files with SQL. Not a problem simple code
and fast.

Jay

-----Original Message-----
From: owner-rpg400-l@midrange.com [mailto:owner-rpg400-l@midrange.com]On
Behalf Of Buck Calabro
Sent: Monday, September 11, 2000 09:45
To: rpg400-l@midrange.com
Subject: RE: page n of x


Jay Myrick wrote:

>You would have an SQL of Select count(*)
>from LIBRARY/FILENAME ORDER BY A, B
>,C. The SQl statment will be different based
>upon if you need to join files and select out
>records with the where clause, but you get
>the point. Once you have the total records
>divide it with lines per page. This approach is
>dynamic when the lines per page change.
>No second pass stuff or complicated APIs.
>Just my humble opinion.

We sort of hashed this out a bit earlier.  This is great for a simple report
where 1 input record = 1 output record.  For slightly more complex reports
where 1 input record = variable output records this is not as feasible.
Imagine a sales report where I read a customer master and list each invoice
sold that customer for that period.  I could write a second SQL statement to
get the total number of invoices, but then I'd have to factor in the number
of "invoice headings..."  Then there's always new pages for each sales
person to throw the count off.

Buck Calabro
Aptis; Albany, NY
"We are what we repeatedly do.
 Excellence, then, is not an act, but a habit." --Aristotle


Billing Concepts Corp., a NASDAQ Listed Company, Symbol: BILL
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