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GNU grep has a -L option that does what you want. I don't know if QSH grep
supports it, though.

-L, --files-without-match
Suppress normal output; instead print the name of each input file from
which no output would normally have been printed. The scanning will stop
on the first match.


"MIDRANGE-L" <midrange-l-bounces@xxxxxxxxxxxx> wrote on 11/11/2016
10:00:06 AM:

From: broehmer@xxxxxxxxxxxxxxx
To: Midrange Systems Technical Discussion <midrange-l@xxxxxxxxxxxx>
Date: 11/11/2016 10:00 AM
Subject: GREP - source members not containing...
Sent by: "MIDRANGE-L" <midrange-l-bounces@xxxxxxxxxxxx>

Hello All,

I've looked thru a ton of GREP documentation and the archives
to find out how to find source members NOT having that text.
Specifically, I'm reviewing our QCLSRC member to see if the
member has "LOGCLP" and hoping to list only those not having
that command.
It would appear that the key is to use the exit side of the result
and I cannot find any example of how to do that.
Does anyone have an example showing how to list members
NOT having something?

This shell command adds to a file of all that have the phrase but I
don't
know how to turn it into one that does not find the text.

qsh cmd('grep -l "LOGCLP" /qsys.lib/cdsrclib.lib/qclsrc.file/* >
/qsys.lib/rrpg.lib/myfile.file/myfile.mbr')

Thanks for any reply,

Bill


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