Re: V7R1 Production LPAR WRKSYSSTS % temp addresses . . . . : 5.555

So 5.555% of temp addresses used leaves you tens (maybe hundreds) of billions of them left. It used to be that each IPL rolled you to a new set of temp addresses, thus lowering the percentage to 0.00somthing. IIRC there are 'only' 32768 sets of temporary addresses so if you IPLed a LOT you could in theory run out and your system would need to be scratch reloaded.

When IBM i moved to RISC the number of addresses in each space went WaaaaaY up so the percentage used dropped commensurately. Then in V5R3 IBM changed the algorithm so that only when you surpass 85% of temp addresses used will you get a new set assigned during an IPL. You will then see 0.00?? % after that IPL.

There is a way (that I cannot recall) to lower the 85% threshold but suffice to say: "You are in no danger here." :-)

- Larry "DrFranken" Bolhuis

www.Frankeni.com
www.iDevCloud.com - Personal Development IBM i timeshare service.
www.iInTheCloud.com - Commercial IBM i Cloud Hosting.

On 7/10/2015 12:29 PM, Steinmetz, Paul wrote:

V7R1 Production LPAR WRKSYSSTS % temp addresses . . . . : 5.555
What are normal or acceptable % for temp addresses?
What is needed to lower this %?
My last IPL had no impact.

http://www-01.ibm.com/support/docview.wss?uid=nas8N1015972


Work with System Status PENCOR05
07/10/15 12:21:50
% CPU used . . . . . . . : 30.1 Auxiliary storage:
Elapsed time . . . . . . : 00:12:50 System ASP . . . . . . : 6983 G
Jobs in system . . . . . : 307642 % system ASP used . . : 44.6186
% perm addresses . . . . : .041 Total . . . . . . . . : 6983 G
% temp addresses . . . . : 5.555 Current unprotect used : 56775 M
Maximum unprotect . . : 61538 M

Type changes (if allowed), press Enter.

System Pool Reserved Max -----DB----- ---Non-DB---
Pool Size (M) Size (M) Active Fault Pages Fault Pages
1 22077.4 4564.2 +++++ .0 .0 .0 .0
2 11059.2 11.4 1714 2.7 17.3 2.9 10.6
3 2007.0 1.4 30 .0 .0 .1 2.3
4 108970.9 1.1 3999 9.2 55.7 13.6 30.6
5 56589.3 <.1 30 2.1 11.4 .3 1.0


Thank You
_____
Paul Steinmetz
IBM i Systems Administrator

Pencor Services, Inc.
462 Delaware Ave
Palmerton Pa 18071

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