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ORDER BY turned out not to be essential. Only five records to deal with.
Definitely nice to know the proper syntax, especially if there had been a
lot more to deal with. Not sure yet, but the duplicates >might< have been
there due to a field that had been forced to a number 1 - a cycle count.
File was prepared elsewhere.

Thanks.

John McKee

On Tue, Feb 24, 2015 at 2:25 PM, Scott Mildenberger <
SMildenberger@xxxxxxxxxxxxxxxxxx> wrote:

with a as (
select siacct, count(siacct) as cnt
from spbsobdp group by siacct)
select * from a where cnt > 1 order by siacct

Scott


-----Original Message-----
From: MIDRANGE-L [mailto:midrange-l-bounces@xxxxxxxxxxxx] On Behalf Of
John McKee
Sent: Tuesday, February 24, 2015 1:19 PM
To: Midrange Systems Technical Discussion
Subject: Locate duplicate accounts in a file

I have a file that is supposed to have one record per account number.
There is at least one duplicate account in the file.

I'm thinking there is a simple(?) way to locate the duplicates with SQL.
But, I am missing something.

I have select siacct, count(siacct) from spbsobdp group by siacct order by
siacct

Which produces a nice list. How can I change the output so only those
records with count > 1 show?

My first thought is to redirect to a file and then query that. Is there
another option?

John McKee
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