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Try the following
select siacct, count(siacct) from spbsobdp group by siacct
having count(siacct) > 1
order by siacct

Alan Shore
E-mail : ASHORE@xxxxxxxx
Phone [O] : (631) 200-5019
Phone [C] : (631) 880-8640
'If you're going through hell, keep going.'
Winston Churchill

-----Original Message-----
From: MIDRANGE-L [mailto:midrange-l-bounces@xxxxxxxxxxxx] On Behalf Of John McKee
Sent: Tuesday, February 24, 2015 3:19 PM
To: Midrange Systems Technical Discussion
Subject: Locate duplicate accounts in a file

I have a file that is supposed to have one record per account number.
There is at least one duplicate account in the file.

I'm thinking there is a simple(?) way to locate the duplicates with SQL.
But, I am missing something.

I have select siacct, count(siacct) from spbsobdp group by siacct order by siacct

Which produces a nice list. How can I change the output so only those records with count > 1 show?

My first thought is to redirect to a file and then query that. Is there another option?

John McKee
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