No, I did not try that. My understanding is that the %date function always
returns a date in ISO format. The 2nd parameter of the %date function
merely tells the function the format the that the first parameter is in.
Since I knew I wanted a date value in *ISO format, I simply used the %date()
form of the function.
-----Original Message-----
From: midrange-l-bounces@xxxxxxxxxxxx
[mailto:midrange-l-bounces@xxxxxxxxxxxx] On Behalf Of Luis Rodriguez
Sent: Tuesday, July 10, 2012 10:52 AM
To: Midrange Systems Technical Discussion
Subject: Re: SQL0180 on SQL insert
Thomas,
I'm curious, Did you try to change your %DATE statements? something like:
Date_ISO = %DATE('2012-07-10':*ISO) ;
Date_USA = %DATE('07/10/2012':*USA) ;
Date_MDY = %DATE('07/10/12' :*MDY) ;
Time_USA = %TIME('11:30 AM' :*USA) ; I just wrote a small program
which what I believe was your original case and could not reproduce the
error. The code for the test program can be found here:
http://code.midrange.com/d7d2224dcb.html
In this case, the compiler (V5R3) generates:
D SQL_00014 129 138D DATFMT(*ISO)
DATE_ISO
D SQL_00015 139 148D DATFMT(*ISO)
DATE_USA
D SQL_00016 149 158D DATFMT(*ISO)
DATE_MDY
D SQL_00017 159 166T TIMFMT(*ISO)
TIME_USA
Regards,
Luis Rodriguez
IBM Certified Systems Expert ? eServer i5 iSeries
midrange.com
