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Rob,
Use the command DSPAUDJRNE ENTTYP(SF) to get the print out.
You must have *SPLFDTA in your system auditing level (QAUDLVL).

Thanks,


On Fri, Sep 9, 2011 at 1:43 PM, <rob@xxxxxxxxx> wrote:

I don't see the type 'D'
I created the spool file in job: 490007/ROB/ROBHQ1
and deleted it in job 490010/ROB/QPADEV000D

Sequence Code Type Object Library Job Time
94551241 T ZC ROBHQ1 13:23:28
94551242 T SF ROBHQ1 13:23:28
94552370 T SF QPADEV000D 13:23:56
94552371 T ZC QPADEV000D 13:23:56

Entry specific data
Column *...+....1....+....2....+....3....+....4....+....5
00001 'DQ04079N058QSPL *FILE Q226774719Q'
00051 'PDSPJOB 0001P1 QUSRSYS 000001 '
00101 ' '
00151 ' '
00201 ' ROBHQ1 ROB 490007 '


Rob Berendt
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Group Dekko
Dept 1600
Mail to: 2505 Dekko Drive
Garrett, IN 46738
Ship to: Dock 108
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http://www.dekko.com





From: Jeff Young <jyoung0950@xxxxxxxxx>
To: midrange-l@xxxxxxxxxxxx
Date: 09/09/2011 12:50 PM
Subject: Audit Journal for Spool files
Sent by: midrange-l-bounces@xxxxxxxxxxxx



I have a client that has all system auditing active.
When I print out the journal data for type *SF (Spool File Action), I see
spool files with type 'C' (created) and 'D' (deleted).
Is there any way to determine the user and job associated with the 'D'
action?
All I seen in the journal display output is the same job and pgm that
created the spool file, not the one that deleted it.

Thanks,

--
Jeff Young
Sr. Programmer Analyst
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