RE: I am converting a date to a floating/double field in SQL. Using day(date_field) returns 1 and not 01. -- MIDRANGE-L

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See the "fun with dates in SQL" page that I just posted. Look for custom
editing, toward the bottom, I think.

http://www.ibm.com/developerworks/data/library/techarticle/0211yip/0211yip3.
html

Dennis Lovelady
http://www.linkedin.com/in/dennislovelady
--
"All progress is based upon a universal innate desire on the part of every
organism to live beyond its income."
-- Samuel Butler

I am converting a date field to a floating field - YYYY-MM-DD to a
floating
field.

The SQL command I am using is FLOAT or DOUBLE and I convert the date
field
as follows:

FLOAT(CHAR( (YEAR(DATE_FIELD) || MONTH(DATE_FIELD) ||
DAY(DATE_FIELD) ))

The system (V5R3) returns the day portion with the leading zero
suppressed
that is 2001-05-09 is returned as 2001059.00000000. It should return
20010509.00000000.

Can anyone help with this problem?

The problem I have is that I cannot convert it back to a date field in
a
later process.

Does anyone have a solution.

TIA

Darryl Freinkel

Assignment 400 Group, Inc.

Tel: 770.321.8562 ext 111 | Fax 770.321.8562 | 2247 La Salle Dr,
Marietta
GA, 30062, USA | PO Box 72556, Marietta, GA 30007-2556

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