RE: Shell question

Very shortly after I posted my question, an answer came to me. It is not elegant, but it works. Actually a bit ugly. The sed command is nicer. What works is this:

file='20'`ls $i|cut -b 5,6``ls $i|cut -b 1-4``ls $i|cut -b 7-10`

Thanks

John McKee


-----Original message-----
From: "Dennis Lovelady" iseries@xxxxxxxxxxxx
Date: Thu, 19 Nov 2009 11:39:31 -0600
To: "'Midrange Systems Technical Discussion'" midrange-l@xxxxxxxxxxxx
Subject: RE: Shell question

Given a file named like this: MMDDYY.TXT I want to rename (or copy it
) to 20YYMMDD.TXT

Might be multiple files, so I would do this:

for i in *.TXT
do
cp $i '20'...
done

There are a few ways to do this. One is directly in the shell, using
something like ${varname#.TXT} but I'm not sure the # character is correct
(could be % or !, maybe?) because I don't have my Korn reference handy. You
can find that online at kornshell.com.

The next would be to pipe the filename through sed: $workname=$(echo
${filename}|sed 's/.TXT//')

There are many other ways to accomplish the same thing, but basically what
you want to do is to get a list of the files, then "for each item" get the
workname, and work at the workname level.

Dennis Lovelady
http://www.linkedin.com/in/dennislovelady
--
My intuition nearly makes up for my lack of good judgment.

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