Re: Selecting last of a group of records

It's the group with the highest timestamp...the records would look like this:

2007-06-13-06.50.51.725000 ORDERH 114938 VYM1
2007-06-13-06.50.52.829000 ORDERD 114938 84598
2007-06-13-07.04.28.104000 ORDERH 114938 VYM1
2007-06-13-07.04.29.214000 ORDERD 114938 84598

Two groups, each consisting of one header and one detail. If the
timestamps were the same within a group, I could use that. I guess I
could find the highest timestamped header and then grab all the detail
after that.

On 7/3/07, rob@xxxxxxxxx <rob@xxxxxxxxx> wrote:

If there's nothing that defines the last group of records, including the
order number, then, no.
What is your definition of the last group of records? Even if you can't
define it in computerese...

Rob Berendt
--
Group Dekko Services, LLC
Dept 01.073
PO Box 2000
Dock 108
6928N 400E
Kendallville, IN 46755
http://www.dekko.com





"Michael Ryan" <michaelrtr@xxxxxxxxx>
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07/03/2007 11:44 AM
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Selecting last of a group of records






I have a file that contains order header and order detail. These
records will always be in the proper order: 1 order header record with
1-n order detail records. I have an index over the data so record
retrieval by order number is very fast. Using embedded SQL, is there
any cool way to get the last group of records? There's nothing that
uniquely identifies the last group - there may be many groups with the
same order number. I was thinking of using a scrollable cursor, going
to the end, then fetching prior. But then I though I could load the
data into a MODS and do the same logic in my program without the fetch
prior. Any ideas? Thanks...
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