Re: New RAID-5 algorithm on V4R5 ?

At 11:05 PM 12/3/00 -0500, you wrote:

Although not well known, but properly documented (if you read the really 
fine print of the Rochester phone book on the page where Olsen is listed), 
here is how RAID works.  If four or more drives are added to an ASP (which 
will soon be known as a "Disk Pool"), the system will create it's own 
parity set for optimal performance purposes.  (AKA, the Maximize Wasted 
Disk Pool command)1

If you want to add five drives to an existing parity set of five drives, 
and do not want to waste an extra disk for parity, add them in groups of 
two and then three.

Al


>Phillip,
>
>   I maintain that I AM correct:
>
>   In your new 170 there are 10 drives.  ALL 10 drives are in the SAME
>RAID set. Thus 8 drives of 7.51G and 2 of 8.58G in the set.  Total
>usable storage of 77.22G.
>
>   Where you are mislead is that on your 620 the drives were of different
>sizes and so must be in different sets - ALL drives in a set must be of
>identical capacity.  On your 170 the drives are all the same size so
>they can all be in one set.  From 4 to 10 drives can be in a single raid
>set.
>
>    Hence the New Math!
>
>    HTH - Larry
>
>Philipp Rusch wrote:
> >
> > Hello Larry,
> >
> > Obviously, youre right !
> >
> > But you are only near the complete truth ...
> >
> > The 620 we were moving from had 5 disks 4.1 gb and 5 disks 8.5 gb,
> > like this, 4 disks of each size form a RAID set and the fifth disk of each
> > set is protected by the others of same size  -  agreed.
> > But, the new 170 is equipped with 10x 8.5 gb and is also having 2 disks
> > with complete capacity and 8 disks with reduced capacity, which I would
> > expect to have the same size as with the 620 because every 4 disks form
> > a set ... (?)
> >
> > Still no clue what is this new math now,
> >
> > regards, Philipp
> >
> > Larry Bolhuis schrieb:
> >
> > > Philipp,
> > >
> > >   It's the new math!
> > >
> > >   Actually you have fallen into the trap of picking a percentage which
> > > is not correct.  To calculate storage lost to RAID you simply subtract
> > > the capacity of 1 disk from the set. This will range from a high of 25%
> > > on the smallest set (1 disk of 4) to a low of 10% on the largest sets (1
> > > disk of 10).
> > >
> > >   Note that the amount lost per drive varies as the RAID data is kept on
> > > either 4 or 8 drives depending on the total number of drives in the set.
> > > (4 drives for sets of 4 to 7 drives and 8 drives for sets of 8 to 10
> > > drives).  Thus WRKDSKSTS will report different sizes for the drives
> > > carrying RAID data than those that are not.
> > >
> > >   Likely your 170 has 10 drives (1 of 10 lost to RAID) and your 620 had
> > > 5 (1 of 5 lost).
> > >
> > >  HTH - Larry
> > >
> > > Philipp Rusch wrote:
> > > >
> > > > Hi all,
> > > >
> > > > I noticed while being at a transition job from one AS/400 to another,
> > > > that there is a difference in how V4R4 and V4R5 handles disk sets on
> > > > a 2740 controller.
> > > > I used to calculate the resulting capacity when "raiding" a set of 
> disks
> > > > on a 274x controller as a loss of about 20% of total capacity.
> > > > When working on a 620-2179 with V4R4 and 6713 disks (8.58 GB)we
> > > > got a resulting capacity of about 6400 MB each, the same disks gave
> > > > me round about 7512 MB on a system 170-2385 with V4R5 and both systems
> > > > were using a 2740 RAID controller.
> > > > Looks to me as if we have a better algorithm as before, because only
> > > > about 10% is used up for running RAID-5 on that set.
>
>--
>Larry Bolhuis
>Arbor Solutions, Inc.
>(616) 451-2500
>(616) 451-2571 -fax
>lbolhuis@arbsol.com
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