Re: MOD function?

instead of using an API, you can simply do it (ignoring complications
if the numbers were negative):

m = mod (a,b) can be computed as:
t = a / b    (where t is integer)
m = a - b * t

----- Original Message -----
From: Goodbar, Loyd (AFS-Water Valley) <LGoodbar@afs.bwauto.com>
To: <MIDRANGE-L@midrange.com>
Sent: Wednesday, May 03, 2000 1:31 PM
Subject: RE: MOD function?


> Thanks, I'll look into it!
> Loyd
>
> -----Original Message-----
> From: Joel Fritz [mailto:JFritz@sharperimage.com]
> Sent: Wednesday, May 03, 2000 11:34 AM
> To: 'MIDRANGE-L@midrange.com'
> Subject: RE: MOD function?
>
>
> Check out the ILE Math APIs.
>
> > -----Original Message-----
> > From: Goodbar, Loyd (AFS-Water Valley)
> > [mailto:LGoodbar@afs.bwauto.com]
> > Sent: Wednesday, May 03, 2000 8:15 AM
> > To: 'midrange-l@midrange.com'
> > Subject: MOD function?
> >
> >
> > Has anyone written a MOD() function? Modulous function gives
> > remainder after
> > division. IE.
> > if mod(12/4) = 0 .....
> >
> > Thanks,
> > Loyd
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