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Its a literal.  It looks like this:

                        
 CALL 'SNDWAKUP'PLIST1  
                        

-----Original Message-----
From: Rob Berendt [mailto:rob@dekko.com]
Sent: Wednesday, November 11, 1998 9:38 AM
To: MIDRANGE-L@midrange.com
Subject: Re: API? SNDWAKUP


Ok, you've got PGMA which calls SNDWAKUP right?  And you've got the source
to PGMA 
also?  Or did you do a DSPPGMREF on PGMA to see what programs are called?

Is SNDWAKUP a literal or a variable?  In other words, when PGMA calls
SNDWAKUP does 
SNDWAKUP have quotes around it?  If not search the source on PGMA until you
find 
SNDWAKUP declared and what value is stored in it.  If you do not have the
source on 
PGMA and you see SNDWAKUP only in the DSPPGMREF then that tells us that it
is a 
literal and not a variable.

The existence, or lack thereof, of a called program will not affect the
compile.  
You can compile the chicken prior to the hatching of it's egg.  The lack of
existence 
will affect the execution of the program.  Try doing a WRKOBJ
*ALL/SNDWAKUP        
In the past you might have been assuming that SNDWAKUP was in a particular
library 
when it is not.  Perhaps the library list during the execution of PGMA is
different 
from your development library list.  The *ALL/SNDWAKUP should find it.  If
not, then 
PGMA will not run.  Unless, all of the following are true:  1)  PGMA is an
ILE program,  
2)  After doing a CRT...MOD on PGMA you have to do a CRTPGM and join it with
a service 
program that contains SNDWAKUP.




Gary_Lehman@mail.mchcp.org on 11/10/98 08:06:31 PM
Please respond to MIDRANGE-L@midrange.com@Internet
To:     MIDRANGE-L@midrange.com@Internet
cc:      

Subject:        API?  SNDWAKUP

Hello,

I came across something(actually another programmer did) in one of our old
RPG programs.  Its a call to a program called SNDWAKUP.  It looks like
nothing we wrote as we have no source and we can't seem to find an object,
yet the program compiles and runs fine.  So I was wondering if it was an
API, cause the routine its called in has to do with processing that the
document describes as IBM IN USE routine.  Looks as if it means when a
record is in use perform some function.  

Does this ring a bell with anyone?

Thanks,

Gary Lehman
Programmer Analyst II
Missouri Consolidated Health Care Plan

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