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Yup, C syntax has some syntactical sugar that can make code hard to read.
It is to bad that for marketing reasons Java kept almost all the syntax of
C.  For "fun" try these [hopefully I got them right]:

With:
int a = 3, b = 3;

1) System.out.println( "a++ is " + a++);
2) System.out.println( "++b is " + ++b);


With:
int a = 5, b = 0;

3) b= a++; 
4) b = ++a;  
5) a = --b; 
6) a = b--; 
7) (a+b)++;

With:
int a = 4, b = 2, c = 3;

8) c *= (a++ / b);


Answers:
1) a++ is 3
2) ++b is 4
3) b is now 5 and a is now 6
4) b and a are now 7
5) a and b are now 6
6) a is now 6 and b is now 5
7) Is illegal! The ++ operator doesn't mean add one.  It means add one to a
variable.  (a+b) is an expression.
8) c  is now 6 and a is now 5; [Computes a/b, multiplies it with c, stores
the answer in c; adds 1 to a]

/Tim
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