Re: julian date

Set up a table with twelve elements in it, containing the max number of
days in each month - you obviously have to work out if its a leap year.

To convert a date to julian eg 13/03/2002, you know its in the third month
so you add the first two table elements together (31 + 28) = 59, and then
add the days in the month you are working on.  Therefore julian date = 59 +
13 = 72.

To go from julian to Gregorian you start at element one, and subtract the
max from the day, repeat this until the result is less than the number of
days in the months.  EG 02072 =
72 - 31 = 41
41 - 28 = 13

13 is less than 31 therefore it is the 13th day of the third month.

Obviously you would code this into a loop.

HTH

JP




                    "Taylor, Mike"
                    <Mike.Taylor@aig.co       To:     
"'cobol400-l@midrange.com'"
                    m>                         <cobol400-l@midrange.com>
                    Sent by:                  cc:
                    cobol400-l-admin@mi       Subject:     julian date
                    drange.com


                    22/03/2002 16:40
                    Please respond to
                    cobol400-l






What is the easiest way to convert a date to julian format.
Thanks

Mike.

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